Logarithmic Algebra

let log2=a, log3=b, and log5=c. express the indicated logarithm in terms of a, b, and c.

log6/25
log 100

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1. log 6/25= log (3*2)/(5^2)
= log 3 + log2 - 2 log5

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bobpursley
2. log 100
= log(25*4)
= log 25 + log 4
= log 5^2 + log 2^2
= 2log5 + 2log2
= 2c + 2a

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