A sample of oxygen at room temperature occupies a volume of 500. L at 1.75 atm. What would be the volume of this gas at 2.50 atm at the same temperature?

350L

P1V1 = P2V2

To solve this problem, we can use Boyle's Law, which states that the volume of a gas is inversely proportional to the pressure when temperature is constant.

Boyle's Law equation: P1 * V1 = P2 * V2

Where:
P1 = initial pressure
V1 = initial volume
P2 = final pressure
V2 = final volume

Given:
P1 = 1.75 atm
V1 = 500 L
P2 = 2.50 atm

Let's plug in the values into the equation and solve for V2:

P1 * V1 = P2 * V2

1.75 atm * 500 L = 2.50 atm * V2

875 atm * L = 2.50 atm * V2

Divide both sides of the equation by 2.50 atm:

V2 = (875 atm * L) / 2.50 atm

V2 = 350 L

Therefore, the volume of the gas at 2.50 atm and the same temperature would be 350 L.

To answer this question, we can use the combined gas law, which relates the volume, pressure, and temperature of a gas. The formula for the combined gas law is as follows:

(P1 * V1) / T1 = (P2 * V2) / T2

where P1 and P2 are the initial and final pressures, V1 and V2 are the initial and final volumes, and T1 and T2 are the initial and final temperatures.

In the given problem, the initial pressure (P1) is 1.75 atm, the initial volume (V1) is 500 L, and the final pressure (P2) is 2.50 atm. The temperature (T1) is not mentioned explicitly, but it is stated that the temperature is the same for both situations. Therefore, we can assume that T1 and T2 are equal.

Using the formula, we can rearrange it to solve for V2:

V2 = (P1 * V1 * T2) / (P2 * T1)

Now let's plug in the values:

V2 = (1.75 atm * 500 L * T1) / (2.50 atm * T1)

T1 cancels out from the equation, so we don't need to know the specific temperature.

V2 = (1.75 * 500) / 2.50

V2 = 875 / 2.50

V2 = 350 L

Therefore, the volume of the oxygen gas at 2.50 atm would be 350 L at the same temperature.