A 330kg crate slides down a 30 degree inclined plane. The total length of the plane is 3,6m. The crate is kept from accelerating by a man who is pushing back on it parallel to the incline.

Calculate the force exerted by the man on the piano

Fc = m*g = 330kg * 9.8N/kg = 3234 N. =

wt. of crate.

Fp = 3234*sin30 = 1617 N. = Force
parallel to the incline.

Fe - Fp = m*a
Fe - Fp = m*0 = 0
Fe = Fp = 1617 N. = Force exerted.

To calculate the force exerted by the man on the crate, we need to consider the forces acting on the crate along the incline. The forces involved are gravity, the normal force, and the force exerted by the man.

First, let's break down the weight of the crate along the incline. The weight of the crate can be calculated using the formula:

Weight = mass * gravitational acceleration
Weight = 330 kg * 9.8 m/s^2 (acceleration due to gravity)
Weight = 3234 N

Next, let's find the component of the weight force acting parallel to the incline. This can be calculated using the formula:

Weight_parallel = Weight * sin(angle of incline)
Weight_parallel = 3234 N * sin(30 degrees)
Weight_parallel = 1617 N

The normal force acting perpendicular to the incline can be calculated using the formula:

Normal force = Weight * cos(angle of incline)
Normal force = 3234 N * cos(30 degrees)
Normal force = 2808 N

Since the crate is not accelerating, the force exerted by the man must balance the component of the weight force acting parallel to the incline. Therefore, the force exerted by the man can be calculated as:

Force_man = Weight_parallel
Force_man = 1617 N

So, the force exerted by the man on the crate is 1617 Newtons.