The teachers in a childcare center are taking their children for a field trip.if each bus takes 40 children, there will be 16 vacant seats. If each bus takes 36 children, 20 children will not get any seats. How many buses are there?
well, it's clear that if there is 1 bus, the numbers work out: 40+16 = 36+20
If there are more buses, then since LCM(40,36) = 360, any multiple of 360 + 56 will also work, with an extra 9 buses if 40/bus, and an extra 10 buses if 36/bus, for each extra 360 kids.
Go to bed it is to late
too late for your spelling and punctuation, apparently...
In how many words can you form the word ALGEBRA?
well, there's
algebraic
algebraically
those are the only words I can think of right off where I can "form the word algebra".
Git
To find the number of buses, we need to solve the given conditions.
Let's assume the total number of children and buses as follows:
- Total number of children = C
- Total number of buses = B
According to the first condition:
If each bus takes 40 children, there will be 16 vacant seats.
This can be written as:
Number of children = Number of buses * Number of seats per bus + Number of vacant seats
C = B * 40 + 16
According to the second condition:
If each bus takes 36 children, 20 children will not get any seats.
This can be written as:
Number of children = Number of buses * Number of seats per bus - Number of children without seats
C = B * 36 - 20
We can now solve these equations simultaneously to find the values of C and B.
From the first equation:
C = 40B + 16
From the second equation:
C = 36B - 20
Since both equations are equal to C, we can equate them:
40B + 16 = 36B - 20
Simplifying the equation:
40B - 36B = -20 - 16
4B = -36
B = -36/4
B = -9
Since the number of buses cannot be negative, the equation does not have a valid solution. It seems there is an inconsistency in the given information. Please double-check the conditions provided or provide additional information to assist further.