How much heat is needed to raise the temp. of 300g of lead (c=0.11 kcal/kg.degreeC)by 5 degC
300 g = .3 kg
so
.3 * .11 * 5 thousand calories
165
Thermal capacity of substances is depends on
To calculate the amount of heat required to raise the temperature of a substance, you can use the following formula:
Q = m * c * ΔT
Where:
Q is the amount of heat in calories
m is the mass of the substance in grams
c is the specific heat capacity of the substance in cal/g·°C
ΔT is the change in temperature in °C
In this case, you want to find the amount of heat required to raise the temperature of 300g of lead by 5°C. The specific heat capacity of lead is given as 0.11 kcal/kg·°C, but we need to convert it to cal/g·°C before using it in the formula.
1 kcal = 1000 cal
1 kg = 1000 g
So, the specific heat capacity of lead in cal/g·°C is 0.11 kcal/kg·°C x 1000 cal/kcal x 1 kg / 1000 g = 0.11 cal/g·°C.
Now, we can substitute the given values into the formula:
Q = m * c * ΔT
Q = 300g * 0.11 cal/g·°C * 5°C
Calculate the result:
Q = 300g * 0.11 cal/g·°C * 5°C
Q = 165 cal
Therefore, 165 calories of heat is needed to raise the temperature of 300g of lead by 5°C.