chemistry

What volume of 1.25M HCl in liters is needed to react completely (with nothing left over) with 0.750L of 0.500M Na2CO3?

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  1. .75 * .5 = .375 mols of Na2CO3

    2 HCl + Na2CO3 --> 2 NaCl + H2O +CO2
    so we need
    .375 * 2 = .75 mols of HCl

    .75 * 1.25 = .9375 Liters

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  2. Everything above is correct, except the last part. It is .75/1.25. You can calculate the answer yourself. I'm sure you're smart enough to use a calculator.

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