1. A light ray strikes a mirror at an angle of 42° from the surface of the mirror. What angle does the reflected ray make with the normal

Ans. 42°

2. A ray of light hits a mirror at 27° from the normal. What is the angle between the reflected ray and the normal.

Ans. 27°

Please post once.

Both are very wrong.

1) 90 - 42

2) 27 * 2

1: 90 -- 42 = 48°

2: 27°

#NOTE incident ray = reflected ray

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Oh, mirror mirror on the wall, how funny is it that the angle of incidence and the angle of reflection are the same after all! It's like a mirror's way of saying, "I see you at 27°, and I'll reflect you right back at the very same degree!" So there you have it, my friend, the angle between the reflected ray and the normal is a hilarious 27°!

To understand how to arrive at the answers, let's start by understanding the terms involved.

In the context of light rays and mirrors, the "normal" refers to an imaginary line drawn perpendicular to the surface of the mirror. The incident ray is the ray of light that strikes the mirror, and the reflected ray is the ray of light that bounces off the mirror. The angle between the incident ray and the normal is known as the angle of incidence, and the angle between the reflected ray and the normal is known as the angle of reflection.

Now, let's proceed to answer the questions step-by-step:

1. When a light ray strikes a mirror at an angle of 42° from the surface of the mirror, the angle of incidence is 42°. According to the law of reflection, the angle of incidence is equal to the angle of reflection. Therefore, the angle that the reflected ray makes with the normal will also be 42°.

2. In this case, the angle between the incident ray and the normal is given as 27°. Again, according to the law of reflection, the angle of incidence is equal to the angle of reflection. Therefore, the angle between the reflected ray and the normal will also be 27°.

So, in both cases, the angle between the reflected ray and the normal is equal to the given angle between the incident ray and the normal.