math

determine vertex, focus and directrix of parabola. then graph the parabola.

first equation:
y^2 -2x-8=0

second equation:
y^2 -4y -12x= 8

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asked by doug
  1. We can't draw graphs for you here. I sugggest you do that yourself

    Rewrite them in the form
    x = a(y-b)^2 + c

    When you have done that, the vertex will be at x=c, y=b. The focus will be located at y=b, x = c + p, and the directrix will be the line x = c - p

    The value of p is
    p = 1/(4a)

    For your first equation,
    x = y^2/2 -4
    so a = 1/2, b = 0 and c = -4

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    posted by drwls

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