Chemistry

10 mL of 0.1 HCl was added to 9mL of water. 10 mL of that solution was added to another 90 mL of water. The student diluted the sample as above 1 time(s). What is the pH of the solution?

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  1. first dilution: you diluted it to 10/19 of .1M, so it is 10/190 M.
    Then you diluted it 10/100 of its concentration, new concentration 10/1900 M

    the statement <The student diluted the sample as above 1 time(s).>> makes no sense to me, it it means my first paragraph, then the concentration is 10/1900 M

    pH=-log(10/1900)=2.28

    check all that.

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    bobpursley

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