i am stumped on this. please help.
Balance the following equation and give the value of the stoichiometric coefficient marked with a question mark.
48KNO3 + _ C12H22O11 ---> ? CO2 +_ N2 + _K2CO3 +_ H2O
thanks
I left the CO2 for you but it will balance.
48KNO3 + 5C12H22O11 ---> ? CO2 + 24N2 + 24K2CO3 + 55H2O
Dr.Bob22 is this correct from sunday jan 21 at 7:14pm
48KNO3 +5C12H22O11 --> CO2 + 24N2 +
24K2CO3 + 55H2O
This is balanced
To balance the given equation, you need to ensure that the same number of each type of atom is present on both sides of the equation. Here's how you can balance it:
1. Start with the atoms that appear in the fewest compounds. In this case, it's K (potassium). There are 48 K atoms on the left-hand side, so we need to have the same number on the right-hand side. Therefore, we put 24K2CO3 on the right side to account for the 48 K atoms.
2. Next, balance C (carbon). There are 5 carbon atoms in each C12H22O11 molecule, so we have 5*12 = 60 carbon atoms on the left side. To balance this, we put 60CO2 on the right side to have the same number of carbon atoms.
3. Now, balance N (nitrogen). There are 48N atoms on the left side, so we need to have the same number on the right side. We put 24N2 on the right side to account for the 48 N atoms.
4. Finally, balance H (hydrogen) and O (oxygen) atoms. There are a total of 132 hydrogen atoms and 120 oxygen atoms on the right side. On the left side, we have 48 KNO3, which contains 48*3 = 144 oxygen atoms. To balance the O atoms, we put 24K2CO3 + 55H2O on the right side. This gives us a total of 144 oxygen atoms and 110 hydrogen atoms, which balances the equation.
The balanced equation is:
48KNO3 + 5C12H22O11 --> 60CO2 + 24N2 + 24K2CO3 + 55H2O
The stoichiometric coefficient marked with a question mark is not necessary to find because the equation is already balanced.