a large cube is built from centimeter cube. faces of large cube are painted 1000 are unpainted what is the edge length ,how many are painted on one face two face and three faces

If 1000 are unpainted, that must mean that the inner dimensions are 10x10x10. To have those completely covered by other cm cubes, which have been painted to some degree, their edges need to be 12x12x12.

Assuming that you are painting only the cm cubes on the surface, the 8 corner cubes would have three faces painted. Those on the 12 edges (minus the 8 corner cubes) would have two faces painted. Calculating the surface area in cm (minus the cm cubes on corners and edges) would give you the cubes that are painted only on one face.

I hope that helps. Thanks for asking.

what is the lenght of an edge of the large cube

how many of the centimeters cubes are painted on one face

To find the length of an edge of the large cube, we need to determine how many smaller cubes make up the large cube. Since the inner dimensions of the large cube are 10x10x10, we can find the number of smaller cubes by multiplying these dimensions: 10 cm x 10 cm x 10 cm = 1000 cm³.

As each side of the smaller cube is 1 cm long, the number of smaller cubes on one side of the large cube (edge length) would be the cube root of 1000: ∛1000 ≈ 10 cm.

So, the length of an edge of the large cube is 10 cm.

Next, let's calculate how many of the cm cubes are painted on only one face. To determine this, we need to subtract the number of cubes that are not painted (1000) and the cubes with more than one face painted from the total number of cubes (1000).

The 8 corner cubes have three faces painted, so we subtract 8 from the total. The 12 edge cubes (excluding the corners) have two faces painted, so we subtract another 12.

Therefore, the number of cm cubes painted on one face would be 1000 - 8 - 12 = 980 cubes.

I hope that clarifies your questions. Let me know if there's anything else I can help with!