math

When a stone is thrown upwards with an initial velocity of v metres per second, it reaches a maximum height of h metres.
h is directly proportional to the square of v.

Calculate the value of v when h = 50

Please help

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  1. y = vt - 4.9t^2

    max height h is at t = v/9.8, so
    h = v^2/19.6

    v^2 = 50*19.6
    v = 31.3 m/s

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  2. Your answer is wrong

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