Evaluate the indefinite integral of the following function,
e^sec2x sec2xtan2x dx
you know that
∫ e^u du = e^u
so, let u = sec(2x)
now you're almost there.
e^sec2x sec2xtan2x dx
∫ e^u du = e^u
so, let u = sec(2x)
now you're almost there.