You take a trip by air that involves three independent flights. If there is an 67% chance each specific leg of the trip is on time, what is the probability all three flights arrive on time? (Round your answer to 3 decimal places.)
Probability =??
To calculate the probability that all three flights arrive on time, we need to multiply the probabilities of each individual flight being on time.
Given that there is a 67% chance each specific leg of the trip is on time, we can say that the probability of a specific flight being on time is 0.67 or 67% expressed as a decimal.
To find the probability of all three flights being on time, we multiply these probabilities together:
Probability = (0.67) * (0.67) * (0.67) = 0.67^3 ≈ 0.300
Therefore, the probability that all three flights arrive on time is approximately 0.300 or 30.0%.
To find the probability that all three flights arrive on time, we can use the concept of independent events.
For each specific leg of the trip, there is a 67% chance it is on time, which means there is a 33% chance it is delayed.
Since the flights are independent, the probability of all three flights being on time is equal to the product of the probabilities of each individual flight being on time.
So, the probability of all three flights arriving on time is calculated as follows:
Probability = (0.67) * (0.67) * (0.67) = 0.300763
Rounding this answer to 3 decimal places gives us a probability of 0.301.
Therefore, the probability that all three flights arrive on time is 0.301 or approximately 30.1%.
P(all) = 3C3 (.67)^3(.33)^0 = 300763
Answer is 0.301
Typo
P(all) = 3C3 (.67)^3(.33)^0 =0. 300763
Answer is 0.301