# algebra

Simplify
(2/3k)+(k/k+1) divided by (k/k+1) -(3/k)

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1. (2/3k)+(k/k+1) = (3k^2+2k+2)/(3k(k+1))
(k/k+1) -(3/k) = (k^2-3k-3)/(k(k+1))

divide the two and you have

(3k^2+2k+2) / 3(k^2-3k-3)

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