1) how does the electric force between two oposite charges changes when the distance between the charges is tripled?

2)how does the electric force between two oposite charges changes when the amount of one charge is doubled?

k Q1 Q2 / d^2

1) if d2 = 3 d 1
then 1/d^2^2 = 1/(3d1)^2 = (1/9) 1/d1^2

2) k Q1 (2 Q2)/d^2 = twice original

To determine how the electric force between two opposite charges changes in these situations, we can use Coulomb's Law, which states that the electric force between two charges is directly proportional to the product of their magnitudes and inversely proportional to the square of the distance between them.

1) If the distance between the charges is tripled, the electric force between them will decrease. To understand how much it changes, we need to use the inverse square relationship. Let's call the initial distance between the charges "d." When it is tripled, the new distance becomes 3d. Plugging this into Coulomb's Law, we see that the electric force decreases by a factor of (1/3)^2 = 1/9. So, the electric force between the two opposite charges will be 1/9 of its initial value.

2) If the amount of one charge is doubled, the electric force between the charges will also change. Let's call the initial charge "q." When it is doubled, the new charge becomes 2q. Plugging this into Coulomb's Law, we see that the electric force increases by a factor of (2)^2 = 4. So, the electric force between the two opposite charges will be 4 times its initial value.