Pre calculus

Find a unit vector in the direction of the given vector.

v=(1,-1)

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  1. for any unit vector in the direction of (a,b)
    ....

    find the length of the vector
    = √(a^2+b^2)

    now divide each component by that magnitude

    to get (a/√(a^2+b^2) , b/√(a^2+b^2)
    or you could write it as
    (1/√(a^2+b^2) (a,b)

    apply this to your vector, let me know what you got

    apply this to your vector

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  2. I got (1/Square root of 2,-1/square root of 2)

    Thanks

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  3. correct

    notice you can check that the magnitude is 1

    magnitude
    = √( (1/√2)^2 + (-1/√2)^2 )
    =√( 1/2 + 1/2)
    = √1
    = 1

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