# Pre calculus

Find a unit vector in the direction of the given vector.

v=(1,-1)

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1. for any unit vector in the direction of (a,b)
....

find the length of the vector
= √(a^2+b^2)

now divide each component by that magnitude

to get (a/√(a^2+b^2) , b/√(a^2+b^2)
or you could write it as
(1/√(a^2+b^2) (a,b)

apply this to your vector, let me know what you got

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2. I got (1/Square root of 2,-1/square root of 2)

Thanks

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3. correct

notice you can check that the magnitude is 1

magnitude
= √( (1/√2)^2 + (-1/√2)^2 )
=√( 1/2 + 1/2)
= √1
= 1

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