Quadrant I
tan terminal= 2
what is csc terminal
tan(any angle) = y/x = 2/1
r^2 = x^2 + y^2
r^2 = 1+4 = 5
r = √5
so sin("terminal") = 2/√5
csc(terminal) = √5/2
BTW, I have never seen or heard of the variable name "terminal" used for an angle.