The final charge on each of the three separated spheres in part (c) is +3.0 µC. How many electrons would have to be added to one of the three spheres to make it electrically neutral?
Divide 3*10^-6 Coulombs by 1.6*10^-19 Coulombs per electron. The will be the number of electrons needed per sphere
1.875x10^13
To find the number of electrons needed to make one of the three spheres electrically neutral, we need to divide the total charge (3.0 µC) by the charge per electron.
The charge per electron is 1.6 * 10^-19 Coulombs.
So, the number of electrons needed per sphere is:
3.0 * 10^-6 C / (1.6 * 10^-19 C/electron) = 1.875 * 10^13 electrons
Therefore, to make one of the three spheres electrically neutral, approximately 1.875 * 10^13 electrons would need to be added.
To find the number of electrons needed to make one of the three spheres electrically neutral, we can divide the total charge on the sphere by the charge of a single electron.
Step 1: Write down the given information:
- Charge on one sphere = +3.0 µC (microcoulombs) = 3.0 * 10^-6 C (coulombs)
- Charge of one electron = 1.6 * 10^-19 C (coulombs)
Step 2: Divide the total charge on the sphere by the charge of a single electron:
Number of electrons = (Charge on the sphere) / (Charge of one electron)
Number of electrons = (3.0 * 10^-6 C) / (1.6 * 10^-19 C)
Step 3: Simplify the expression:
Number of electrons = (3.0 / 1.6) * (10^-6 / 10^-19) electrons
Number of electrons = 1.875 * 10^13 electrons
So, to make one of the three spheres electrically neutral, approximately 1.875 * 10^13 electrons would need to be added to it.