How many milliliters of 0.326 M HCl would be required to titrate 5.48 g KOH?

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  1. HCl + KOH ==> KCl + H2L
    mols KOH = grams/molar mass
    mols KOH = mols HCl from the 1:1 ratio (coefficients) in the balanced equation.
    Then M HCl = mols HCl/L HCl. You know mols and M, solve for L and convert to mL.

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