Three uniform spheres are fixed at the positions shown

in the diagram. Assume they are completely isolated and
there are no other masses nearby.

(a) What is the magnitude of the force on a 0.20 kg particle
placed at the origin (Point P)? What is the direction of this
force?
(b) If the 0.20 kg particle is placed at (x,y) = (-500 m, 400 m)
and released from rest, what will its speed be when it reaches
the origin?
(c) How much energy is required to separate the three masses
so that they are very far apart?

To solve these questions, we can use the concept of the gravitational force between masses. This force can be calculated using Newton's law of universal gravitation:

F = G * (m1 * m2) / r^2

Where:
F is the magnitude of the gravitational force between the two masses,
G is the gravitational constant (approximately 6.674 × 10^−11 N m^2 / kg^2),
m1 and m2 are the masses of the two objects, respectively, and
r is the distance between the centers of the two objects.

Now let's apply this formula to each question:

(a) To find the magnitude of the force on a 0.20 kg particle placed at the origin (Point P), we need to calculate the gravitational forces between this particle and each of the three fixed spheres. Then, we can add the vector components of these forces to find the net force.

Let's assume the mass of each fixed sphere is given as m.

The force between the particle at the origin and the sphere at (0 m, -1000 m) can be calculated using the formula:

F1 = G * (0.20 kg * m) / (1000 m)^2

The force between the particle at the origin and the sphere at (-1000 m, 0 m) can be calculated using the formula:

F2 = G * (0.20 kg * m) / (1000 m)^2

The force between the particle at the origin and the sphere at (1000 m, 0 m) can be calculated using the formula:

F3 = G * (0.20 kg * m) / (1000 m)^2

Since the forces are acting in different directions, we need to consider their vector components. The net force can be found by adding the x-components and y-components separately:

Fx = F1 + F2 + F3
Fy = -F1 + F2 - F3 (negative signs arise from the direction of the forces)

The magnitude of the net force can be found using the Pythagorean theorem:

|F| = sqrt(Fx^2 + Fy^2)

The direction of the force can be found using trigonometry. The angle θ can be determined by:

θ = atan(Fy / Fx)

(b) To find the speed of the 0.20 kg particle when it reaches the origin from (-500 m, 400 m), we need to calculate the work done by the gravitational force.

The work done is given by the formula:

W = -ΔU = m * (U_f - U_i)

Here, ΔU is the change in gravitational potential energy, which is equal to the work done by the gravitational force. U_f is the gravitational potential energy at the final position (the origin), and U_i is the gravitational potential energy at the initial position.

The initial potential energy can be calculated using the formula:

U_i = -G * (m * M) / r_i

Where M is the mass of each fixed sphere and r_i is the initial distance between the particle and the origin.

The final potential energy can be calculated using the formula:

U_f = -G * (m * M) / r_f

Where r_f is the distance between the particle and the origin when it reaches the origin.

The total work done is:

W = m * (U_f - U_i)

The kinetic energy at the final position can then be calculated using the work-energy theorem:

K_f = W

Finally, the speed at the final position can be found using the formula:

v_f = sqrt(2 * K_f / m)

(c) To calculate the energy required to separate the three masses so that they are very far apart, we need to consider the gravitational potential energy.

The gravitational potential energy is given by the formula:

U = -G * (m1 * m2) / r

We need to calculate the potential energy between each pair of masses and then add them up.

Let's consider mass m1 as the particle at the origin and masses m2, m3, and m4 as the three fixed spheres.

The potential energy between m1 and m2 is:

U_12 = -G * (m1 * m2) / r_12

The potential energy between m1 and m3 is:

U_13 = -G * (m1 * m3) / r_13

The potential energy between m1 and m4 is:

U_14 = -G * (m1 * m4) / r_14

The total potential energy is:

U_total = U_12 + U_13 + U_14

This will give us the amount of energy required to separate the three masses to a very far distance.

Note: It's important to plug in the correct values for the masses, distances, and other constants to get accurate results.