based on the balanced eq: c6h12+9O2->6CO2+6H2O
calculate the molecules of CO2 formed when 174 molecules of H20 form.
im not exactly sure how to start this problem.
Okay, this is what I think... it seems to be too easy.
So the reaction produces 6 moles of CO2 and 6 moles of H2O, that mean they have a ratio of 1 to 1. In other word, when you have 174 moles of H2O, then you'll also have 174 moles of CO2... so there isn't really any calculation you need to do in this problem.
One slight problem.
174 molecules is not 174 moles.
174 molecules x (1 mol/6.02 x 10^23 molecules) = # mols CO2 produced if you want to go that way. Otherwise, the reasoning is sound; therefore, 174 molecules of water will be formed when 174 molecules of CO2 are formed.
To solve this problem, you need to use the coefficients in the balanced equation to determine the mole ratio between water (H2O) and carbon dioxide (CO2).
The balanced equation tells us that for every 6 molecules of water consumed, 6 molecules of carbon dioxide are produced.
Step 1: Calculate the mole ratio between water and carbon dioxide using the balanced equation.
In this case, the mole ratio is 6:6, or 1:1. This means that for every 6 molecules of water (H2O), 6 molecules of carbon dioxide (CO2) are produced.
Step 2: Use the mole ratio to find the number of CO2 molecules produced when 174 molecules of H2O form.
Since the mole ratio is 1:1, we can conclude that when 174 molecules of water (H2O) form, the same number of molecules of carbon dioxide (CO2) will be produced.
Therefore, 174 molecules of H2O will produce 174 molecules of CO2.
To solve this problem, you need to use the balanced equation that relates the reactants and products.
The balanced equation is: C6H12 + 9O2 -> 6CO2 + 6H2O
First, you need to determine the molar ratio between H2O and CO2. From the balanced equation, you can see that for every 6 molecules of CO2 produced, 6 molecules of H2O are also produced. Therefore, the molar ratio is 6:6, or simply 1:1.
To find the number of CO2 molecules formed when 174 molecules of H2O are consumed, you can set up a proportion using the molar ratio:
(174 H2O)/(1 CO2) = (x H2O)/(6 CO2)
Cross-multiplying:
174 H2O = x H2O * 6 CO2
Dividing both sides by 6 CO2:
174 H2O / 6 CO2 = x H2O
Now, you can solve for x, which represents the number of CO2 molecules formed.
x = (174 H2O / 6 CO2) = 29 CO2
Therefore, when 174 molecules of H2O react, 29 molecules of CO2 are formed.