Hello! This is my take home final for my chemistry class and I can use any resources to help me solve the questions. Can someone help me get started on all of them? Thanks…

(note: he wants us to solve them using stoichiometry)

1. The resting calorie use of a human is about 1,000 calories per day. In other words, just to perform the functions necessary to live, you need 1,000 calories of energy. In large part that energy comes from glucose in a reaction that cant be simplified as the combustion of glucose. The function of the lungs is to provide oxygen for that reaction as well as remove the waste. The air that the lungs take in is .05% carbon dioxide and 21% oxygen, and the lungs can hold 6 liters of air. If carbon dioxide concentrations over 8% are lethal, how long can a person theoretically hold their breath? Human body temperature is 37 C, and the pressure in the lungs is 1 atm.
Hint: the written and balanced equation for this reaction is: (numbers after underscore are moles of the element)

(C_6 H_12 0_6) + 60_2 → 6CO_2 + (6H_2 O)

2. Nitrogen tri-Iodide is an extremely unstable compound that will decompose explosively with as little pressure as a fly walking on it. Assuming that the temperature of the revolting gases is at 25 C at 1 atm, and the density of NI_3 is 1.2 g/cm^3, what is the ratio of the volume of reactants to the volume of products?

3. A rough approximation of the relationship between altitude and pressure below 30,000 ft. can be given with the equation: -0.0024h + 101.33P, where “h” is the altitude in ft/. and P is pressure in kPa. Likewise, temperature is modeled as -.002h + 288= T, where “h” is altitude in ft. and T is temperature in Kelvins. Using this information, what is the equation for the volume (in Liters) of a weather balloon released at sea level and rising to 30,000 ft. if the initial volume of the balloon is 100,000L? If the balloon can only expand to twice its original volume, what is it maximum altitude before it pops? (conversion between celcius and kelvins is “273 + C= K” )

If your teacher allows you to have others work the exam for you, report him to the dean. Somebody is getting cheated out of an education.

actually he does have our administrators permission to do this, especially since we have an in-class final where we cannot use any resources or notes. i am not a cheater and i don't want the answers, i just want to know how to get started on these problems, as i have stated before

chimeastry thing

Sure! I can help you get started on these questions using stoichiometry. Here's an explanation for each question:

1. To calculate how long a person can hold their breath, we need to determine the time it takes for the carbon dioxide concentration in the lungs to reach 8%.

First, we need to find the number of moles of carbon dioxide and oxygen in 6 liters of air using the given percentages.

- The concentration of carbon dioxide is 0.05% or 0.0005, so the moles of carbon dioxide = 0.0005 * 6 liters.
- The concentration of oxygen is 21% or 0.21, so the moles of oxygen = 0.21 * 6 liters.

Next, we can use stoichiometry to relate the moles of carbon dioxide to the moles of glucose consumed.

From the balanced equation, we see that 1 mole of glucose produces 6 moles of carbon dioxide. Therefore, the moles of glucose consumed = (moles of carbon dioxide) / 6.

Now, we can calculate the amount of glucose consumed per day by multiplying the moles of glucose consumed by the molar mass of glucose (180.16 g/mol).

Finally, we divide the total energy released from the combustion of glucose (represented by the 1,000 calories) by the energy released per gram of glucose (3,750 calories/g) to find the grams of glucose consumed per day.

To determine how long a person can hold their breath, we need to divide the grams of glucose consumed per day by the grams of glucose consumed per minute, assuming the reaction occurs at a constant rate.

2. To find the ratio of the volume of reactants to the volume of products, we need to determine the number of moles of nitrogen tri-iodide (NI3) and the number of moles of gases formed from the explosive decomposition reaction.

Given the density of NI3 (1.2 g/cm^3), we can calculate the volume of NI3 using its molar mass.

From the balanced equation, we know that 2 moles of NI3 decompose to produce 3 moles of gas. Therefore, the moles of gases formed = (2 moles of NI3) * (3 moles of gas / 2 moles of NI3).

Finally, we can calculate the ratio of the volume of reactants to the volume of products by dividing the volume of NI3 by the volume of the gases formed.

3. To find the equation for the volume of a weather balloon released at sea level and rising to 30,000 ft, we need to use the information provided about altitude, pressure, and temperature.

Given the equation -0.0024h + 101.33P for pressure and -.002h + 288 for temperature, we can substitute the values for altitude (h) into these equations.

Using Boyle's Law (P1V1 = P2V2) and the ideal gas law (PV = nRT), we can relate the pressure, volume, temperature, and number of moles of gas for the weather balloon at sea level and 30,000 ft.

With the initial volume of the balloon (100,000 L), we can determine the number of moles of gas at sea level.

To find the maximum altitude before the balloon pops, we can set the final volume to twice the initial volume (200,000 L) and then solve for h in the equation -0.0024h + 101.33P = -0.002h + 288 using the information given.

These are the general steps you can follow to get started on each question. Let me know if you need further assistance with any specific part!