a ball is dropped from the top on an 80-m high building. what speed does the ball have in falling 3.5 s?
What speed does the ball in the first question have in falling 3.5 s?
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I told you in the first line, 34.3 m/s
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in 4 sec
d = .5 * 9.81 *16 = 78.5 meters
so no
v = g t = 9.81 * 3.5 = 34.3 m/s
but what if it hit the ground?
d = (1/2) g t^2 = 60 meters
so it has not hit ground yet, whew
So how do you do that exact problem but if it is 4.0seconds?
suggama d
A ball is dropped from the top of a 84-m-high building. What speed does the ball have in falling 3.4 s?
To find the speed at which the ball is falling after 3.5 seconds, we can use the equations of motion.
The equation that relates distance, initial speed, time, and acceleration in free fall is:
distance = initial speed * time + (1/2) * acceleration * time^2
In this case, the ball is dropped, so its initial speed is zero. The acceleration due to gravity is approximately 9.8 m/s^2.
Using this equation, we can rearrange it to solve for the final speed:
final speed = initial speed + (acceleration * time)
Since the initial speed is zero, the equation simplifies to:
final speed = acceleration * time
Plugging in the values, we get:
final speed = 9.8 m/s^2 * 3.5 s
final speed = 34.3 m/s
Therefore, after 3.5 seconds, the ball will have a speed of 34.3 m/s.
does this change the answer... the ball is dropped from the top of an 80-m-high building. does the ball reach the ground in 4.0 s?
I got no, it falls only 78 m in 4.0 s
What speed does the ball in the first question have in falling 3.5 s?