Generate a detailed image of a physics experiment, showcasing a stationary 2.0 kg object on a table near the surface of the earth. The table is engaging in passive resistance via friction, with coefficients for static and kinetic friction being .80 and 0.65 respectively. A horizontal force of 5N is being applied to the object, causing it to adjust its position on the table. Please ensure a clear, real-world representation of this scenario, displaying all the elements involved but make sure the image contains no text.

A stationary 2.0 kg object is located on a table near the surface of the earth. The coefficient static friction between the surface is .80 and the coefficient of the kinetic friction is 0.65. A horizontal force of 5N is applied to the object. Determine the force of friction. Determine the accelaration of the object. How should we change the magnitude of the horizontal applied force to get an acceleration of 1.5 m/s^2? What is the friction force at that acceleration?

m g = weight = 2*9.81 = 19.62 N

static friction max = .8*19.62 = 15.7 N
kinetic friction = .65*19.62 = 12.8 N

5 N does not move it. Friction resists with 5 N by third law

F - 12.8 = 2 (1.5)
F = 15.8 N to get 1.5 m/s^3 acceleration, it is moving now so friction force is -12.8 as soon as it starts

Лнвч

Ah, friction! The ultimate buzzkill for objects trying to have a good time on a table. Let's calculate the force of friction for our stationary object.

The force of friction can be determined using the formula F_friction = μ * F_normal, where μ is the coefficient of friction and F_normal is the normal force.

For our stationary object, the normal force is equal to the weight of the object, which is given by F_weight = m * g, where m is the mass of the object (2.0 kg) and g is the acceleration due to gravity (approximately 9.8 m/s^2).

Substituting the values, we find F_weight = 2.0 kg * 9.8 m/s^2 = 19.6 N.

Now, let's calculate the force of friction:

F_friction = μ * F_normal = (0.80) * (19.6 N) = 15.68 N.

So, the force of friction is 15.68 N for our stationary object.

Now let's find the acceleration of the object when a horizontal force of 5 N is applied.

The net force acting on the object is given by Newton's second law: F_net = m * a, where F_net is the net force, m is the mass of the object, and a is the acceleration.

We can rearrange the equation to find the acceleration: a = F_net / m.

Substituting the values, we have a = 5 N / 2.0 kg = 2.5 m/s^2.

So, the object will have an acceleration of 2.5 m/s^2 when a horizontal force of 5 N is applied.

To achieve an acceleration of 1.5 m/s^2, we need to change the magnitude of the horizontal applied force.

Using the same formula as before, we rearrange it to find F_net: F_net = m * a.

Substituting the values, we have F_net = 2.0 kg * 1.5 m/s^2 = 3.0 N.

Therefore, to achieve an acceleration of 1.5 m/s^2, we need to decrease the magnitude of the horizontal applied force to 3.0 N.

Finally, let's determine the friction force at this acceleration.

Using the formula F_friction = μ * F_normal, we can substitute in the new values.

F_friction = (0.65) * (19.6 N) = 12.74 N.

So, at an acceleration of 1.5 m/s^2, the friction force will be 12.74 N.

Hope I could help you slide through those calculations smoothly!

To determine the force of friction, we need to compare the applied force to the maximum static friction force.

Step 1: Calculate the maximum static friction force
The maximum static friction force is given by:
fs_max = μs * N
Where μs is the coefficient of static friction and N is the normal force exerted by the table, which is equal to the weight of the object.

Step 2: Calculate the weight of the object
Weight = mass * gravitational acceleration
The gravitational acceleration near the surface of the Earth is approximately 9.8 m/s^2.

Weight = 2.0 kg * 9.8 m/s^2
Weight = 19.6 N

Step 3: Calculate the maximum static friction force
fs_max = 0.80 * 19.6 N
fs_max = 15.68 N (rounded to two decimal places)

Therefore, the maximum static friction force is 15.68 N.

Step 4: Compare the applied force to the maximum static friction force
The force of friction when the object is stationary (static friction) is equal to the force applied.

Force of friction = 5 N

Now let's determine the acceleration of the object.

Step 1: Calculate the force of friction
The force of friction when the object is moving (kinetic friction) is given by:
fk = μk * N
Where μk is the coefficient of kinetic friction and N is the normal force.

Step 2: Calculate the kinetic friction force
fk = 0.65 * 19.6 N
fk = 12.74 N (rounded to two decimal places)

Therefore, the force of friction when the object is moving is 12.74 N.

Step 3: Calculate the net force
Net force = applied force - force of friction
Net force = 5 N - 12.74 N
Net force = -7.74 N (negative sign indicates opposite direction)

Step 4: Calculate the acceleration
The acceleration can be calculated using Newton's second law: F = ma

Net force = mass * acceleration
-7.74 N = 2.0 kg * acceleration

Acceleration = -7.74 N / 2.0 kg
Acceleration = -3.87 m/s^2 (negative sign indicates opposite direction)

Therefore, the acceleration of the object is -3.87 m/s^2.

Now let's determine how to change the magnitude of the horizontal applied force to get an acceleration of 1.5 m/s^2.

Step 1: Calculate the net force required for the desired acceleration
Net force = mass * desired acceleration
Net force = 2.0 kg * 1.5 m/s^2
Net force = 3 N

Therefore, the magnitude of the horizontal applied force should be 3 N to achieve an acceleration of 1.5 m/s^2.

Lastly, let's determine the friction force at that acceleration.

Step 1: Calculate the net force
Net force = applied force - force of friction
We know that the applied force is 3 N.

Step 2: Calculate the force of friction
Force of friction = applied force - net force

Force of friction = 3 N - (-7.74 N) (since the net force is in the opposite direction as the applied force)

Force of friction = 3 N + 7.74 N
Force of friction = 10.74 N (rounded to two decimal places)

Therefore, the friction force at the acceleration of 1.5 m/s^2 is 10.74 N.

To determine the force of friction, we first need to determine whether the object is in a state of static or kinetic friction.

1. Force of friction:
a) Static friction: When the object is at rest and not moving, the force of friction is given by the product of the coefficient of static friction (μs) and the normal force (N).
μs = 0.80
N = mass × acceleration due to gravity = 2.0 kg × 9.8 m/s^2

Therefore, the force of static friction (fs) = μs × N

b) Kinetic friction: When the object is in motion, the force of friction is given by the product of the coefficient of kinetic friction (μk) and the normal force.
μk = 0.65
N = 2.0 kg × 9.8 m/s^2

Therefore, the force of kinetic friction (fk) = μk × N

2. Acceleration of the object:
To find the acceleration of the object, we can use Newton's second law, which states that the net force (F) acting on an object is equal to the mass (m) of the object multiplied by its acceleration (a).

F = ma

Given: F = 5 N and m = 2.0 kg

Substitute the given values to find the acceleration (a) of the object.

3. Changing the magnitude of the applied force to get an acceleration of 1.5 m/s^2:
To find the new magnitude of the applied force, we can rearrange the equation from step 2:

F = ma

Given: m = 2.0 kg and a = 1.5 m/s^2

Substitute the given values to find the new magnitude of the applied force (F).

4. Friction force at the new acceleration:
Once we determine the new magnitude of the applied force, we can use the same steps as in step 1 to find the new force of friction.

Remember to always consider the direction of the forces involved and whether they are positive or negative in the chosen coordinate system.