Na2SO4(aq)+CaI2(aq)→CaSO4(s)+2NaI(aq) as net ionic
To write the net ionic equation for the given reaction (Na2SO4(aq) + CaI2(aq) → CaSO4(s) + 2NaI(aq)), you need to first write the balanced molecular equation, then write the ionic equation, and finally simplify it to the net ionic equation.
1. Balanced Molecular Equation:
The balanced molecular equation is obtained by combining the ions of the reactants and products into a balanced equation.
2Na+ + SO4^2- + Ca^2+ + 2I- → CaSO4 + 2Na+ + 2I-
2. Ionic Equation:
In the ionic equation, any reactant or product that is a strong electrolyte (dissociates completely into ions in solution) is written as ions.
2Na+ + SO4^2- + Ca^2+ + 2I- → CaSO4(s) + 2Na+ + 2I-
3. Net Ionic Equation:
The net ionic equation is obtained by removing the spectator ions (ions that are present on both sides of the equation and do not participate in the reaction).
In this case, the Na+ and I- ions appear on both sides of the equation and do not participate in the reaction. Therefore, they are considered spectator ions and should be eliminated.
Net Ionic Equation:
SO4^2- + Ca^2+ → CaSO4(s)
So, the net ionic equation for the given reaction is SO4^2- + Ca^2+ → CaSO4(s).
To determine the net ionic equation for the given reaction, you will need to first write the balanced molecular equation and then break it down into its respective ions.
Step 1: Write the balanced molecular equation
The given reaction is:
Na2SO4(aq) + CaI2(aq) → CaSO4(s) + 2NaI(aq)
Step 2: Split the reactants and products into their respective ions
Na2SO4 dissociates into two Na+ ions (sodium) and one SO4^2- ion (sulfate).
CaI2 dissociates into one Ca^2+ ion (calcium) and two I- ions (iodide).
CaSO4 does not dissociate, as it is a solid.
2NaI dissociates into two Na+ ions and two I- ions.
So, the ionic equation can be written as:
2Na+(aq) + SO4^2-(aq) + Ca^2+(aq) + 2I-(aq) → CaSO4(s) + 2Na+(aq) + 2I-(aq)
Step 3: Cancel out the spectator ions
Spectator ions are those that appear on both sides of the equation and do not participate in the actual reaction. In this case, the Na+ ions are present on both sides, so they can be canceled out.
The net ionic equation is:
SO4^2-(aq) + Ca^2+(aq) → CaSO4(s)
net ionic?
Ca++ + SO4-- > CaSO4