a piece of metallic iron (10 moles) was dissolved in concentrated hydrochloric acid. the reaction formed iron (II) chloride and hydrogen gas. how many moles of iron (II) chloride were formed?

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  1. Fe + 2HCl ==> FeCl2 + H2
    1 mol Fe = 1 mol FeCl2; therefore,
    10 mol Fe = 10 mols FeCl2.

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