what is
lead (II) acetate + hydrogen sulphide -->
Pb(C2H3O2)2 + H2S -->
how do i figure it out?
To figure out the reaction between lead (II) acetate and hydrogen sulphide, you can start by writing the balanced chemical equation. Here are the steps:
Step 1: Determine the formulas of the reactants and products:
- Lead (II) acetate: Pb(C2H3O2)2
- Hydrogen sulphide: H2S
Step 2: Write the unbalanced equation by combining the reactants on the left side and the products on the right side:
Pb(C2H3O2)2 + H2S → ??
Step 3: Determine the products:
When lead (II) acetate reacts with hydrogen sulphide, it forms lead sulphide (PbS) and acetic acid (CH3COOH).
Step 4: Write the balanced equation:
Pb(C2H3O2)2 + H2S → PbS + CH3COOH
The balanced equation shows that lead (II) acetate reacts with hydrogen sulphide to form lead sulphide and acetic acid.
To determine the products of a chemical reaction, you need to follow a few steps. In this case, the reaction you provided is between lead (II) acetate (Pb(C2H3O2)2) and hydrogen sulfide (H2S). Here's how you can figure out the products:
Step 1: Determine the chemical formula for both reactants.
- Lead (II) acetate (Pb(C2H3O2)2) consists of a lead (Pb) cation and acetate (C2H3O2) anions.
- Hydrogen sulfide (H2S) consists of a hydrogen (H) cation and a sulfide (S) anion.
Step 2: Identify the type of reaction.
In this case, the reaction can be classified as a double displacement reaction because both reactants are compounds that exchange ions.
Step 3: Swap the anions between the cations.
In the reaction, lead (II) acetate will swap its acetate anions (C2H3O2-) with hydrogen sulfide's sulfide anion (S2-).
Step 4: Write the balanced equation.
The products of the reaction will be lead (II) sulfide (PbS) and acetic acid (CH3COOH).
So, the balanced equation is:
Pb(C2H3O2)2 + H2S --> PbS + 2CH3COOH
Therefore, the products of the reaction between lead (II) acetate and hydrogen sulfide are lead (II) sulfide and acetic acid.
You remember two things.
a. Reactions go to completion for one of three reasons.
1. a ppt is formed. For this you need to know the solubility rules. In this case PbS is formed which is a ppt.
2. a gas is formed. For this you need to know what is a gas and what isn't. In the periodic table there is some unity in that H2, N2, O2, F2, Cl2, (and perhaps Br2) are gases + common gases such as C2H2, CH4, CO, CO2, H2S etc.
3. a weak electrolyte is formed. Weak electrolytes are weak acids, weak bases, H2O, and one or two others. In this case HC2H3O2 (acetic acid) is formed and that is a weak acid.
So there are two reasons for this reaction.
Pb(C2H3O2)2 + H2S ==> PbS(s) + 2HC2H3O2