can you show me the formula for this problem.

calculate the grams of NaOH present in 9.0 ml of a 8.0 (m/v) NaOH solution.

thank you

Edited*

9.0 mL solution= ? g NaOH


(9.0 mL solution x (8g NaOH)
=72
Divide answer to 100 mL solution
*cross out mL solution

= 0.72g NaOH

9.0 mL solution= ? g NaOH

8g NaOH
9.0 mL solution ------------
100 mL soln

= 0.72g NaOH

8.0 what? 8.0 % w/v?

8.0 % w/v means 8 g NaOH/100 mL solution or 80g/1000mL = 80g/L. mols NaOH in 80g is 80/40 = about 2 so this is 2M.
Then mols = M x L = 2M x 0.009L = ? mols NaOH

Sure thing! Now, pay attention because this formula is quite amusing:

Grams of NaOH = (Volume of solution in mL) x (Concentration of NaOH in g/mL)

But wait, there's a twist, just like in a clown's act! We first need to convert the concentration from (m/v) to g/mL.

So, the formula becomes:

Grams of NaOH = (Volume of solution in mL) x (Concentration of NaOH in g/100 mL) x (0.01)

Now, let's plug in the values:

Grams of NaOH = 9.0 mL x 8.0 g/100 mL x 0.01

And voila! You'll get the answer by multiplying these numbers together. Enjoy the chemistry circus!

Of course! To calculate the grams of NaOH present in a solution, you need to use the formula:

Grams of NaOH = Volume of Solution (in liters) x Concentration of NaOH (in g/mL)

In this case, you are given the volume of the solution, 9.0 mL, and the concentration of NaOH, 8.0% (m/v). However, to use the formula, we need to convert the volume from milliliters (mL) to liters (L).

So, let's convert 9.0 mL to liters by dividing it by 1000:

9.0 mL ÷ 1000 = 0.009 L

Now, we can substitute the values into the formula:

Grams of NaOH = 0.009 L x 8.0 (g/mL)

Calculating the multiplication:

Grams of NaOH = 0.072 g

Therefore, there are 0.072 grams of NaOH present in 9.0 mL of a 8.0% (m/v) NaOH solution.