Carlos invested his savings in two investment funds. The amount he invested in Fund A was $8000 less than the amount he invested in Fund B. Fund A returned a 8% profit and Fund B returned a 4% profit. How much did he invest in Fund B, if the total profit from the two funds together was $1040?

amount in B ---- x

amount in A -----x - 8000

.04x + .08(x-8000) = 1040
times 100
4x + 8(x-8000) = 104000

I am sure you can finish it

14,000

Ivan invested his savings in two investment funds. The amount he invested in Fund A was

$5000
less than the amount he invested in Fund B. Fund A returned a
7%
profit and Fund B returned a
4%
profit. How much did he invest in Fund B, if the total profit from the two funds together was
$1520
?

To find out how much Carlos invested in Fund B, let's follow these steps:

1. Let's assume the amount Carlos invested in Fund B is "x" dollars.
2. According to the problem, the amount he invested in Fund A was $8000 less than the amount he invested in Fund B. So, the amount invested in Fund A can be represented as (x - $8000).
3. The profit from Fund A is 8% of the amount invested in Fund A, which means the profit from Fund A can be calculated as 8% of (x - $8000), or 0.08 * (x - $8000).
4. Similarly, the profit from Fund B is 4% of the amount invested in Fund B, which means the profit from Fund B can be calculated as 4% of x, or 0.04 * x.
5. According to the problem, the total profit from the two funds together is $1040. So, the equation can be written as:

0.08 * (x - $8000) + 0.04 * x = $1040

6. Now, we can solve this equation to find the value of x, which represents the amount Carlos invested in Fund B.

Let's solve the equation step by step:

0.08x - 0.08($8000) + 0.04x = $1040
0.08x - $640 + 0.04x = $1040
0.12x - $640 = $1040
0.12x = $1040 + $640
0.12x = $1680

Divide both sides of the equation by 0.12 to isolate x:

x = $1680 / 0.12
x = $14,000

Therefore, Carlos invested $14,000 in Fund B.