Calculate the concentration in % (m/m) of a solution containing 20.5 g of LiF dissolved in 340.0 g of H2O.
a.1.14% (m/m)
b.5.69% (m/m)
c.6.03% (m/m)
d.6.42% (m/m)
b) 5.69
% by mass = [(mass solute)/(mass solute+mass solvent)]*100 = ?
To calculate the concentration in % (m/m), we need to divide the mass of the solute by the mass of the solution and then multiply by 100.
The mass of the solute (LiF) is given as 20.5 g.
The mass of the solution (H2O) is given as 340.0 g.
Concentration (m/m) = (mass of solute / mass of solution) * 100
Substituting the given values:
Concentration (m/m) = (20.5 g / 340.0 g) * 100
Calculating the concentration:
Concentration (m/m) = 0.06029 * 100
Concentration (m/m) = 6.03%
Therefore, the concentration in % (m/m) of the solution is c. 6.03%.
To calculate the concentration in % (m/m) of a solution, you need to divide the mass of the solute by the mass of the solution, and then multiply by 100.
In this case, the mass of the solute (LiF) is given as 20.5 g, and the mass of the solution (H2O) is given as 340.0 g.
So, the concentration (C) can be calculated as:
C = (mass of solute / mass of solution) * 100
C = (20.5 g / 340.0 g) * 100
C = 0.06029411764 * 100
C ≈ 6.03
Therefore, the concentration in % (m/m) of the solution is approximately 6.03%.
So the correct answer is option c.6.03% (m/m).