chemistry

what is the pH of a NaOH solution whose concentraiton is 4.5 * 10^-5 M.

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  1. NaOH ==>Na^+ + OH^-
    The trick is to know that NaOH is a strong base; i.e., it is ionized in water solution 100%. Therefore, (NaOH) = (OH^-)
    So (OH^-) = 4.5 x 10^-5 M
    Change that to pOH, and subtract from 14.
    pH about 9.6 or so.

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