A ball is thrown vertically upward with an initial velocity of 135 feet per second, the ball’s height after t second is s(t) = 135t – 22t
How to calculate average velocity from 1 to 3 seconds?
According to my knowledge of physics,
s(t) = 135t - 16t^2
Anyway, average velocity = total.distance/total.time
So, that would be (s(3)-s(1))/(3-1)
To calculate the average velocity from 1 to 3 seconds, you need to determine the displacement of the ball within that time frame and divide it by the time taken.
First, we need to find the position of the ball at 1 second and at 3 seconds.
s(1) = 135(1) - 22(1) = 113 feet
s(3) = 135(3) - 22(3) = 339 feet
Next, we find the displacement by subtracting the initial position at 1 second from the final position at 3 seconds.
Displacement = s(3) - s(1) = 339 - 113 = 226 feet
Finally, we calculate the average velocity by dividing the displacement by the time interval.
Time interval = 3 - 1 = 2 seconds
Average velocity = Displacement / Time interval = 226 feet / 2 seconds = 113 feet per second
Therefore, the average velocity from 1 to 3 seconds is 113 feet per second.