Determine the volume of base ml needed to prepare the following 500 ml of 0.18 % NaOH SOLUTION USING A 10.0 % NaOH SOLUTION
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To determine the volume of the base in milliliters (mL) needed to prepare a 500 mL solution of 0.18% NaOH using a 10.0% NaOH solution, you need to use the formula:
Concentration × Volume = Concentration × Volume
Let's break down the information given:
Initial Concentration (C1) = 10.0% NaOH
Initial Volume (V1) = unknown (we will solve for it)
Final Concentration (C2) = 0.18% NaOH
Final Volume (V2) = 500 mL
Now we can plug in the values and solve for V1:
(10.0% NaOH) × (V1) = (0.18% NaOH) × (500 mL)
To solve this equation, we need to express the concentrations as decimal fractions:
(0.10) × (V1) = (0.0018) × (500 mL)
Simplifying further:
0.10V1 = 0.0018 × 500
Now, solve for V1 by dividing both sides of the equation by 0.10:
V1 = (0.0018 × 500) / 0.10
V1 = 9 mL
Therefore, you would need 9 mL of the 10.0% NaOH solution to prepare 500 mL of a 0.18% NaOH solution.