In desperate need of help!
solve by factoring.
1. x^2=-25+10x
2. 2x^2+9x=5
3. The length of a square is 4x-3. Find the area in terms of x.
1. x^2 - 10x + 25 = 0
25 = -5 * -5
(x-5)(x-5) = 0
x-5 = 0
X = 5
x-5 = 0
X = 5
Solution set: X = 5, and 5.
2. 2x^2 + 9x -5 = 0
A*C = 2 * -5 = -10 = -1*10
2x^2 + (-x+10x) - 5 = 0
(2x^2-x) + (10x-5) = 0
x(2x-1) + 5(2x-1) = 0
(2x-1)(x+5) = 0
2x-1 = 0
2x = 1
X = 1/2
x+5 = 0
X = -5
Solution set: X = -5, and X = 1/2.
3. A=(4x-3)(4x-3). Do the multiplication