Math Help

In desperate need of help!

solve by factoring.

1. x^2=-25+10x

2. 2x^2+9x=5

3. The length of a square is 4x-3. Find the area in terms of x.

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  1. 1. x^2 - 10x + 25 = 0
    25 = -5 * -5
    (x-5)(x-5) = 0

    x-5 = 0
    X = 5

    x-5 = 0
    X = 5

    Solution set: X = 5, and 5.

    2. 2x^2 + 9x -5 = 0
    A*C = 2 * -5 = -10 = -1*10

    2x^2 + (-x+10x) - 5 = 0
    (2x^2-x) + (10x-5) = 0
    x(2x-1) + 5(2x-1) = 0
    (2x-1)(x+5) = 0

    2x-1 = 0
    2x = 1
    X = 1/2

    x+5 = 0
    X = -5

    Solution set: X = -5, and X = 1/2.

    3. A=(4x-3)(4x-3). Do the multiplication

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