Mr. Smith has a scale drawing of his rectangular swimming pool. The lenght is 15" and the height is 11". The scale is 1 inch = 2 feet.

What is the perimeter of the actual pool? Do I add 15 + 15 + 11 + 11 to get the perimeter?

your answer to 15 + 15 + 11 + 11 would still be in inches.

The sum is 52 inches, but each inch is 2 feet.
So the perimeter of the pool would be 104 feet.

To find the perimeter of the actual pool, you need to convert the dimensions from the scale drawing into real measurements. You have correctly identified that the length in the scale drawing is 15 inches and the height is 11 inches.

Given that the scale is 1 inch = 2 feet, you need to convert the dimensions by multiplying them by the scale factor. The scale factor is determined by the ratio of real measurements to the measurements in the drawing, which in this case is 2 feet per inch.

For the length, you multiply 15 inches by the scale factor of 2 feet per inch:
15 inches * 2 feet/inch = 30 feet

For the height, you multiply 11 inches by the scale factor of 2 feet per inch:
11 inches * 2 feet/inch = 22 feet

Now, you have the actual dimensions of the pool: a length of 30 feet and a height of 22 feet. To find the perimeter, you add up all the sides.

Perimeter = 2 * (length + height)
= 2 * (30 feet + 22 feet)
= 2 * (52 feet)
= 104 feet

So, the perimeter of the actual pool is 104 feet.