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How do you calculate the preparation of 0.1M HCl using 33% HCl?
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You need to know the density of the HCl solution (the 33%) and you need to know how much of the 0.1M you wish to prepare.
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10). What is the molarity of an HCl solution if 42.5 mL of a 0.110 M KOH solution is needed to titrate a 25.0-mL sample of the
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from the equation HCl + KOH -> KCl + H2O 1 mole of HCl reacts with 1 mole of KOH Then if we use
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5) How many mL of 1M HCl is used to make the following dilutions?
a) 100mL of 0.1M HCl = b) 250mL of 0.5M HCl= c) 10ml of 0.01M
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Use the dilution formula for these. c1v1 = c2v2 c = concn v = volume for a. 100 mL x 0.1M = ? mL x
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For an experiment, we used 10 mL of HCl. We are then to find the moles of it without any other information given. Is this right?
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Were you given this density value? (1.19 g / mL) ? A published value for concentrated HCl at 1.19
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Describe the preparation of 100 mL of 6.0 M HCL from a concentrated solution that has a specific gravity of 1.18 and is 37%
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Ans.: (1000mL/1L)(1.18 g/mL)(0.37)(1mol HCl/36.5 g HCl) = 11.96 M We want to make 100 mL of 6.0 M:
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describe the preparation of 100ml of 6.0M HCl from a concentrated solution that has a specific gravity of 1.18 and is 37% w/w
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To prepare 100ml of 6.0M HCl from a concentrated solution with a specific gravity of 1.18 and is 37%
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Describe the preparation of 100 mL of 6.0 M HCL from a concentrated solu-tion that has a specific gravity of 1.18 and is 37%
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First you determine by calculation the molarity of the 37% solution. 1.18 g/mL x 1000 mL x 0.37 x
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In the preparation of one liter of 2.5 M HCl solution, what is the volume of HCl
concentrated (37% w / w, d = 1.19 g / ml) to be
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Concentrated HCl is commonly 11.8M. So you are diluting it 11.8/2.5 times, or 4.72 times. That
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A sample of 0.0020 mole of HCl is sissolved in water t omake a 2000ml solution. Calculate the molarity of the HCl solution, the
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To calculate the molarity of the HCl solution, we need to use the formula: Molarity (M) = Number of
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A 0.2299 N acid is prepared by mixing 100 ml of 0.1234 N H2SO4 and 0.3200 N HCl. How much HCl is needed in the preparation of
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118.2
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