one number is 3 times another number and their sum is -16
y is one number
x is the other number.
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x + y = -16
3x = y
solve for x and y.
Post your work if you need further assistance.
To solve the given system of equations, let's start by rearranging the first equation:
x + y = -16
Subtracting y from both sides, we get:
x = -16 - y
Now we can substitute this expression for x into the second equation:
3x = y
Substituting -16 - y for x, we have:
3(-16 - y) = y
Expanding and simplifying:
-48 - 3y = y
Now, let's solve for y:
-48 = 4y
Dividing both sides by 4:
-12 = y
So, we have found the value of y. Now, let's substitute this value back into one of the original equations to solve for x:
x + (-12) = -16
x - 12 = -16
Adding 12 to both sides:
x = -16 + 12
x = -4
Therefore, the solution to the system of equations is x = -4 and y = -12.