Physics

A 5.00-g bullet is fired into a 500-g block of wood suspended as a ballistic pendulum. the combined mass swings up to a height of 8.00 cm. What was the magnitude of the momentum of the combined mass immediately after the collision?
Answer
a. 0.394 kg·m/s
b. 0.632 kg·m/s
c. 6.25 ´ 10–3 kg·m/s
d. 6.25 kg·m/s

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  1. total mass = .5 + .005 = .505 kg

    potential energy = m g h = .505*9.81*.08
    = .396 Joules
    that is Ke at bottom
    (1/2) (.505) v^2 = .396
    v = 1.25 m/s
    momentum = m v = .505 * 1.25
    = .633 kg m/s

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