How to get the answer to a formula if I=�ã2P/L relates the coefficient of self-induction, L (in henry's), the energy P stored in an electronic circuit (in joules), and the current I (in amps). Find I if P=120 and L=70.

The example I have to go by does not help with rounding to the nearest thousandth. Find I if P=90 and L=70
Formula I=�ã2P/L
=�ã2*(90)/70
=�ã180/70
= 1.604 amps

rounding to the nearest thousandth? I find it difficult this is an issue in college.

Consider the number...

ab.cdefghij

a is the tens digit
b is the units digit
c is the tenths digit
d is the hundreths digit
e if the thousandths digit
f is the ten thousands digit

take a look at f. Is if 5 or greater? if so, increase the thousandths by one, then drop f,g,h and so on.

Ok thanks

To find the value of I using the given formula I=�ã2P/L, you need to substitute the given values for P and L into the formula.

In the given example, P=90 and L=70.

To calculate I, follow these steps:

1. Substitute the values of P and L into the formula:
I = �ã2P/L
I = �ã2*(90)/70

2. Simplify the expression inside the square root:
I = �ã180/70

3. Calculate the square root:
I ≈ 1.604 amps

The rounded value of I to the nearest thousandth is approximately 1.604 amps.

Therefore, the value of I, given P=90 and L=70, is approximately 1.604 amps.