In the following reaction, how many liters of oxygen produce 560 liters of
carbon dioxide in the oxidation of methane, given that both gases are at STP?
CH4 + 2O2 �¨ CO2 + 2H2O
When gases are used you may use volumes as if it were mols.
560 L CO2 x (2 mol O2/1 mol CO2) = 560 x 2/1 = ?
To determine how many liters of oxygen produce 560 liters of carbon dioxide in the oxidation of methane, we can use the stoichiometry of the balanced chemical equation:
1 mol of CH4 + 2 mol of O2 -> 1 mol of CO2 + 2 mol of H2O
From Avogadro's Law, we know that 1 mol of any ideal gas occupies 22.4 liters at standard temperature and pressure (STP).
To convert liters of carbon dioxide (CO2) to moles, we divide the volume by 22.4:
560 L CO2 / 22.4 L/mol = 25 mol CO2
From the balanced equation, we can see that 1 mol of CO2 is produced for every 2 mol of O2 consumed. Therefore, we need twice the number of moles of O2:
25 mol CO2 * (2 mol O2 / 1 mol CO2) = 50 mol O2
Finally, we can convert the moles of oxygen (O2) to liters by multiplying by 22.4:
50 mol O2 * 22.4 L/mol = 1120 L O2
Therefore, 1120 liters of oxygen produce 560 liters of carbon dioxide in the oxidation of methane at STP.
To determine how many liters of oxygen produce 560 liters of carbon dioxide in the given reaction, we need to use the stoichiometry of the balanced equation.
The balanced equation is:
CH4 + 2O2 → CO2 + 2H2O
From the balanced equation, we can see that for every 1 mole of methane (CH4) reacted, we need 2 moles of oxygen (O2) to produce 1 mole of carbon dioxide (CO2).
To solve this problem, follow these steps:
1. Convert the given volume of carbon dioxide to moles:
Since both gases are at STP (Standard Temperature and Pressure), we can use the molar volume of gases at STP, which is 22.4 liters per mole.
Moles of CO2 = 560 liters / 22.4 liters per mole = 25 moles
2. Use the stoichiometry of the balanced equation to determine the moles of oxygen required:
For every 1 mole of carbon dioxide, we need 2 moles of oxygen.
Moles of O2 = 2 moles of O2/mole of CO2 * 25 moles of CO2 = 50 moles
3. Convert the moles of oxygen to liters using the molar volume at STP:
Moles of O2 = 50 moles
Volume of O2 = 50 moles * 22.4 liters/mole = 1120 liters
Therefore, to produce 560 liters of carbon dioxide in the given reaction, we would need 1120 liters of oxygen.