Which of the following is a solution of x² + 14x + 112 = 0? If necessary, round to the nearest hundredth. (1 point)

• x = –0.24
• x = –4.24
• 4.24
• no solution

c

b
d
b

I did this one last year

http://www.jiskha.com/display.cgi?id=1362104847

If u go to connexus algebra student is 100% correct I just took the quick check

Yeah algebra student is right guys, got 100%

To find the solution of the given quadratic equation x² + 14x + 112 = 0, you can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / (2a)

In this equation, a, b, and c represent the coefficients of the quadratic equation. In our case, a = 1, b = 14, and c = 112.

Substituting the values into the formula:

x = (-(14) ± √((14)² - 4(1)(112))) / (2(1))

Simplifying further:

x = (-14 ± √(196 - 448)) / 2

x = (-14 ± √(-252)) / 2

Since we have a negative value under the square root, we can conclude that there are no real solutions to this equation. Hence, the correct answer is "no solution".