Which of the following is a solution of x² + 14x + 112 = 0? If necessary, round to the nearest hundredth. (1 point)
• x = –0.24
• x = –4.24
• 4.24
• no solution
c
b
d
b
I did this one last year
http://www.jiskha.com/display.cgi?id=1362104847
If u go to connexus algebra student is 100% correct I just took the quick check
Yeah algebra student is right guys, got 100%
To find the solution of the given quadratic equation x² + 14x + 112 = 0, you can use the quadratic formula:
x = (-b ± √(b² - 4ac)) / (2a)
In this equation, a, b, and c represent the coefficients of the quadratic equation. In our case, a = 1, b = 14, and c = 112.
Substituting the values into the formula:
x = (-(14) ± √((14)² - 4(1)(112))) / (2(1))
Simplifying further:
x = (-14 ± √(196 - 448)) / 2
x = (-14 ± √(-252)) / 2
Since we have a negative value under the square root, we can conclude that there are no real solutions to this equation. Hence, the correct answer is "no solution".