In lacrosse, a ball is thrown from a net on the end of a stick by rotating the stick and forearm about the elbow. If the angular velocity of the ball about the elbow joint is 30.0 rad/s and the ball is 1.05 m from the elbow joint, what is the velocity of the ball?
v=(1.05 m)(30 rads/s)= 31.5 m/s
This didn't even answer my questions.
To find the velocity of the ball, we can use the relationship between angular velocity and linear velocity. The formula is given by:
v = rω
where:
v = linear velocity
r = distance from the rotation axis (in this case, the elbow joint)
ω = angular velocity
In this case, the angular velocity (ω) is given to be 30.0 rad/s, and the distance from the elbow joint (r) is 1.05 m. Plugging in these values into the formula, we get:
v = (1.05 m)(30.0 rad/s)
v ≈ 31.5 m/s
Therefore, the velocity of the ball is approximately 31.5 m/s.