Complete the following nuclear reaction:
^16,v8 O + ^4, v2 He → ________ + ^19, v10 Ne
1p
1n
2H
3H
To complete the nuclear reaction, we need to balance the equation by ensuring that the total number of protons and neutrons on both sides of the reaction are equal.
Let's break down the reaction and determine the number of protons and neutrons on each side:
On the left side:
^16,v8 O: This represents Oxygen-16. It has 8 protons and 8 neutrons.
^4, v2 He: This represents Helium-4. It has 2 protons and 2 neutrons.
On the right side:
^19, v10 Ne: This represents Neon-19. It has 10 protons and 9 neutrons.
To balance the equation, we need to add or remove particles to make the number of protons and neutrons the same on both sides.
On the left side, we have a total of 8 protons and 10 neutrons. To balance the protons on the right side, we need to add 2 protons. The only option that fits this requirement is Helium-4 (^4 He), which has 2 protons.
Therefore, the balanced equation is:
^16,v8 O + ^4, v2 He → ^20, v10 Ne + ^19, v10 Ne