A quality control inspector found flaws in 13 out of 150 sweaters. Find the probabillity that a sweater has a flaw. Round to nearest tenth of a %
Suppose the company produces 600 sweaters/day. How many WILL have flaws?
PS! I have sent them in separatly.
3 step problem!!!
13/150 = .08666 times 100 = 8.6666...% to nearest tenth percent = 8.7%
.087 * 600 = 52
could also say 600 * (13/150) = 52
To find the probability that a sweater has a flaw, you need to divide the number of flawed sweaters by the total number of sweaters.
Step 1: Find the probability that a sweater has a flaw.
Probability = (Number of flawed sweaters) / (Total number of sweaters)
Probability = 13 / 150
To round to the nearest tenth of a percent, we can calculate the probability as a decimal and then convert it to a percentage.
Probability = 13 / 150 ≈ 0.08667
Probability ≈ 0.08667 * 100 ≈ 8.7%
So, the probability that a sweater has a flaw is approximately 8.7%.
Step 2: Calculate the number of flawed sweaters produced per day.
To find the number of flawed sweaters produced per day, you need to know the production rate and the probability of a sweater having a flaw.
Number of flawed sweaters produced per day = (Number of sweaters produced per day) * (Probability of a sweater having a flaw)
Number of flawed sweaters produced per day = 600 * 0.08667
Number of flawed sweaters produced per day ≈ 52
Therefore, approximately 52 sweaters will have flaws per day.
I hope this explanation helps! Let me know if you have any further questions.