A force of 15N acts in the forward direction on a carton of 3kg. Suppose a friction force of 6N opposes the carton motion.
Find the following:
1) the net force
2) the acceleration of the carton
1. 15 - 6 = 9 N. = Net force.
2. a = Fn/m = 9/3 = 3 m/s^2.
To find the net force and acceleration of the carton, we need to use Newton's second law of motion, which states that the net force (F_net) acting on an object is equal to the mass (m) of the object multiplied by its acceleration (a). We can calculate both of these values using the given information.
1) The net force (F_net) can be found by subtracting the force of friction (F_friction) from the applied force (F_applied):
F_net = F_applied - F_friction
In this case, the applied force is 15N and the friction force is 6N, so,
F_net = 15N - 6N = 9N
Therefore, the net force acting on the carton is 9N.
2) To find the acceleration (a) of the carton, we can rearrange Newton's second law of motion formula:
F_net = m * a
Given that the mass (m) of the carton is 3kg and the net force (F_net) is 9N,
9N = 3kg * a
Divide both sides of the equation by 3kg:
a = 9N / 3kg = 3 m/s²
Therefore, the acceleration of the carton is 3 m/s².