The variables arr1 and arr2 have been declared as pointers to integers . An array of 10 elements has been allocated, its pointer assigned to arr1, and the elements initialized to some values . Allocate an array of 20 elements , assign its pointer to arr2, copy the 10 elements from arr1 to the first 10 elements of arr2, and initialize the remainder of the elements of arr2 to 0.
To perform the task described, you would need to follow these steps:
1. Declare the variables `arr1` and `arr2` as pointers to integers:
```c++
int *arr1, *arr2;
```
2. Allocate memory for an array of 10 elements and assign its pointer to `arr1`:
```c++
arr1 = new int[10];
```
3. Initialize the elements of `arr1` to some values:
```c++
// Example initialization
for (int i = 0; i < 10; i++) {
arr1[i] = i + 1; // Assigning values 1 to 10
}
```
4. Allocate memory for an array of 20 elements and assign its pointer to `arr2`:
```c++
arr2 = new int[20];
```
5. Copy the 10 elements from `arr1` to the first 10 elements of `arr2`:
```c++
for (int i = 0; i < 10; i++) {
arr2[i] = arr1[i];
}
```
6. Initialize the remainder of the elements of `arr2` to 0:
```c++
for (int i = 10; i < 20; i++) {
arr2[i] = 0;
}
```
After following these steps, you will have allocated two arrays (`arr1` and `arr2`) and initialized them accordingly. The first 10 elements of `arr2` will contain the same values as the elements in `arr1`, while the remaining 10 elements of `arr2` will be initialized to 0.