calculate the molarity of the solution prepared by dissolving 16.45g NH4NO3 in water to make 250.mL solution.
mol NH4NO3 = grams/molar mass
Then M = mols/L solution. You know mols and L soln, solve for M.
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To calculate the molarity of a solution, you need to know the moles of the solute (NH4NO3) and the volume of the solution in liters.
Let's calculate the moles first:
Step 1: Convert the mass of NH4NO3 from grams to moles using its molar mass.
Molar mass of NH4NO3 = (1 * atomic mass of N) + (4 * atomic mass of H) + (3 * atomic mass of O)
= (1 * 14.01 g/mol) + (4 * 1.01 g/mol) + (3 * 16.00 g/mol)
= 80.04 g/mol
Moles of NH4NO3 = mass / molar mass
= 16.45 g / 80.04 g/mol
= 0.2055 mol
Step 2: Convert the volume of the solution from milliliters to liters.
Volume of solution = 250 mL = 0.250 L
Step 3: Calculate the molarity (M) using the formula:
Molarity (M) = moles of solute / volume of solution (in liters)
= 0.2055 mol / 0.250 L
= 0.822 M
Therefore, the molarity of the solution prepared by dissolving 16.45 g NH4NO3 in water to make a 250 mL solution is 0.822 M.
To find the molarity of a solution, you need to know the amount of solute (NH4NO3) in moles and the volume of the solution in liters. Here's how you can calculate the molarity:
Step 1: Calculate the number of moles of NH4NO3.
To do this, you need to convert the mass of NH4NO3 (16.45g) to moles using its molar mass.
The molar mass of NH4NO3 is calculated as follows:
M(N) + 4 * M(H) + 3 * M(O)
M(N) = 14.01 g/mol (atomic mass of nitrogen)
M(H) = 1.01 g/mol (atomic mass of hydrogen)
M(O) = 16.00 g/mol (atomic mass of oxygen)
Calculating the molar mass:
M(NH4NO3) = 14.01 + 4 * 1.01 + 3 * 16.00
= 80.05 g/mol
Now, you can calculate the number of moles of NH4NO3:
moles = mass / molar mass
moles = 16.45 g / 80.05 g/mol
moles ≈ 0.2057 mol
Step 2: Convert the volume of the solution to liters.
The volume given is 250. mL. To convert it to liters, divide by 1000.
volume = 250. mL / 1000
volume = 0.250 L
Step 3: Calculate the molarity.
Molarity (M) is defined as moles of solute per liter of solution.
Molarity = moles / volume
Molarity = 0.2057 mol / 0.250 L
Molarity ≈ 0.823 M
Therefore, the molarity of the solution prepared by dissolving 16.45g NH4NO3 in water to make a 250. mL solution is approximately 0.823 M.