which line is perpendicular to the line y=2/3x+3
y=-3x/2+13/2
all lines of the type
y = (-3/2)x + b , where b is any real number
would be perpendicular to your given line
Where there any choices?
so just make sure the answer starts with y = (-3/2)x ...
To find a line that is perpendicular to the line y = (2/3)x + 3, we need to determine the slope of the given line.
The given line is in slope-intercept form, y = mx + b, where m represents the slope.
In this case, the slope is 2/3.
To find a line perpendicular to this one, we need to find the negative reciprocal of the slope. Therefore, the negative reciprocal of 2/3 is -3/2.
So, any line with a slope of -3/2 will be perpendicular to the line y = (2/3)x + 3.
The equation of a line with the slope -3/2 can be written as y = (-3/2)x + c, where c is the y-intercept.
Therefore, any line of the form y = (-3/2)x + c will be perpendicular to the line y = (2/3)x + 3.