A 70 kg man stands on an accurate spring scale inside the elevator. Given that the lift can accelerate and decelerate at 2.2 m/s^2, Compute the man's maximum and minimum weight.

To calculate the man's maximum and minimum weight in the elevator, we need to consider the different scenarios where acceleration affects the reading on the spring scale.

1. Maximum Weight:
We will calculate the maximum weight when the elevator is accelerating upward. In this scenario, the man's weight will be added to the force exerted on the scale due to the acceleration. The net force acting on the man is given by:

F_net = m * (g + a)

Where:
m = mass of the man = 70 kg
g = acceleration due to gravity = 9.8 m/s^2
a = acceleration of the elevator = 2.2 m/s^2

Substituting the values into the equation gives:

F_net = 70 * (9.8 + 2.2)
= 70 * 12
= 840 N

Hence, the man's maximum weight is 840 Newtons.

2. Minimum Weight:
We will calculate the minimum weight when the elevator is accelerating downward or decelerating upward. In these scenarios, the force due to the acceleration is subtracted from the man's weight. The net force acting on the man is given by:

F_net = m * (g - a)

Using the same values for mass and acceleration as before:

F_net = 70 * (9.8 - 2.2)
= 70 * 7.6
= 532 N

Therefore, the man's minimum weight is 532 Newtons.

In summary, the man's weight on the spring scale in the elevator can vary between a maximum of 840 Newtons when the elevator is accelerating upward, and a minimum of 532 Newtons when the elevator is accelerating downward or decelerating upward.